A wholesaler buys motorcycles to stockists at a 12% profit The stockists sell the motorcycles to retailers at a 15% profit That's why they can ask you to find an expression for dy/dx Then saying f(x,y)=0 means f is zero along the curve defined by y(x) #9 unscientific 1,734 13 Dick said You think of y as being some function of x That's why they can ask you to find an expression for dy/dx Then saying f(x,y)=0 means f is zero along the curveNeither the real function nor accordingly its derivative can be defined When the function itself cannot be defined its derivative by implicit differentiation is meaningless 1 for the correct answer You might consider showing the analysis behind the observation that x
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13.if x^(y)+y^(x)=2 then find (dy)/(dx)-Answer (1 of 2) We have to be careful and distinguish partial derivatives from differentials!Solution for Find the solution dy y dx A y = y = x cx8 y = y2 00 B Q 2Verify the final value theorem for the function 3t²e¬4t and determine its steady state value
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Calculus Find dy/dx y=x^2e^x y = x2ex y = x 2 e x Differentiate both sides of the equation d dx (y) = d dx (x2ex) d d x ( y) = d d x ( x 2 e x) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more stepsTake log on both sides == y log x = log u == y*1/x logx * dy/dx (by products rule) = 1/u du / dx ==du/dx = x y (y/x logx dy/dx) let y x = v ;In this problem we have been given that divided by dx That is 10 x And we have to determine the value of Y So in order to get the value of Y, let's take Dx to the other side and let's integrate both sides And upon integration we observe that integration of divide that's just why and integration of 10 X That is log of mud psychics And there will also come a constant C
Let t = xy and u = yx Then lnt = ln(xy) and lnu = ln(yx) It follows that 1 t = dy dx lnx → xy(lnx( dy dx) y x) Doing the same, we get that yx(lny x y ( dy dx)) Thus the derivative of the entire function is given by xylnx( dy dx) xy( y x) yxlny yx x y ( dy dx) = 0Transcribed Image Text Find and then simplify whenever possible dy d²y dx dx?If the general solution of `(x2)dy(6x5)dx=0` is `y=6xk log(x2)c,` then `k=` asked 2 days ago in Differential Equations by Somyek ( 1k points) class12
Multiply both sides of the equation by x\left (xy\right) Multiply both sides of the equation by x ( − x y) x\left (xy\right)\frac {\mathrm {d} (y)} {\mathrm {d}x}=dy x ( − x y) d x d ( y) = d y Use the distributive property to multiply x by xy Use the distributive property to multiply x by − x yTill infinite Find dy/dx Please give the solutionWrite in the form y=x^y since x^x^x^x is till infinite, we can consider it to be y, then take l Book a Trial With Our Experts ×Workdone =(1/2)kx^2 given, stretching the string from 4 to 12
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The question is if Y is equal to X b that will be divided by X square c then find the value of DY by DX so let's start so what we have given we have given by will be close to a x b that'll be divided by X square c so now we have to differentiate by the act that will be caused by using question troll then we can write X square c then the differentiation of x b we have a that will be mineSolution (1) – y (y x log y) / x (y log x x) x y y x = 1 log (x y y x) = log 1 log (x y) log (y x) = 0 log x (dy / dx) y (1 / x) log y (x / y) (dy / dx) = 0 dy / dx = – y (y x log y) /Y = ∫ f (x) dx C, which gives general solution of the differential equation Example Solve the given differential equation d y d x = x x 2 1 Solution We have, d y d x = x x 2 1 dy = x x 2 1 dx Integrating both sides, we get ∫ dy = ∫ x x 2 1 dx dy = 1 2 2 x x 2 1 dx
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Answered Apr 12 by AnantShaw (290k points) y = xsinx ∴ ∴ dy dx = d dx xsinx d y d x = d d x x s i n x (1) (∵ d dx constant = 0) ( ∵ d d x c o n s t a n t = 0) Let xsinx = z Then sin log x = log z (by taking log on both sides) ⇒ sinx x logxcosx = 1 z dz dx s i n x x l o g x c o s x = 1 z d z d x (on differentiatingClick here👆to get an answer to your question ️ If x^y = y^x , then find dydx Solve Study Textbooks Guides Join / Login >> Class 12 >> Maths >> Continuity and Differentiability >> Logarithmic Differentiation >> If x^y = y^x , then find dydx QuestionA first order Differential Equation is Homogeneous when it can be in this form dy dx = F ( y x ) We can solve it using Separation of Variables but first we create a new variable v = y x v = y x which is also y = vx And dy dx = d (vx) dx = v dx dx x dv dx (by the Product Rule) Which can be simplified to dy dx = v x dv dx
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Given xyx 2sin , find dxdy by using implicit differentiation Then the correct answer is Then the correct answer is 15 The equations of the tangent line and normal line to the curve xyx 2sin at the point ,0 are given by (1) xy 3 and xy 3 (2) xy 3 and xy 3How to find dy/dx by implicit differentiation given that xy = x yHere's the 4 simple steps we will take in order to find dy/dx from the given equation xyThis same result would be obtained by solving for y so that y = x 2 1, from which dy/dx = 2x In this example it is easier to first solve for y and then differentiate, but this will not always be the case Example 1 Find the slope of the tangent line to the graph of the equation xy x = 1 at that point on the graph whose first coordinate is
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Find dy/dx y = square root of x y = √x y = x Use n√ax = ax n a x n = a x n to rewrite √x x as x1 2 x 1 2 y = x1 2 y = x 1 2 Differentiate both sides of the equation d dx (y) = d dx (x1 2) d d x ( y) = d d x ( x 1 2) The derivative of y y with respect to x x is y'Click here👆to get an answer to your question ️ Find dy/dx of xy = e^x y Solve Study Textbooks Guides Join / Login >> Class 12 >> Maths >> Continuity and Differentiability >> Logarithmic Differentiation >> Find dy/dx of xy = e^x y Maths Q Question If y x = x y, then find d x d y If `y=((a xb))/((x^2c))` , then find `dy/dx` Books Physics NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless Chemistry NCERT P Bahadur IITJEE Previous Year Narendra Awasthi MS Chauhan Biology NCERT NCERT Exemplar NCERT Fingertips Errorless Vol1 Errorless Vol2 Maths
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Here we look at doing the same thing but using the "dy/dx" notation (also called Leibniz's notation) instead of limits We start by calling the function "y" y = f(x) 1 Add Δx When x increases by Δx, then y increases by Δy y Δy = f(x Δx) 2 Subtract the Two FormulasShare It On Facebook Twitter Email 1 Answer 1 vote answered by paayal (148k points) selected by Vikash Kumar Best answer Put x y = u and y x = v ∴ (i) becomesFind in terms of x and y x°y° = 3 Q Compute the work required to stretch a spring from 4 to 12 cm past equilibrium, assuming that the A the equation to find workdone is;
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RHS x log(2) => log(2) log(2) is a constant so x dissapears So we get (1/y)(dy/dx) = log(2) 4) We want to find dy/dx, which is on the LHS To get this dy/dx on its own we can multiply both sides by y So we get dy/dx = y log(2) 5) To finish this question we need to sub in for y and then we have an answer for dy/dx Recall y=2^x (fromD x dx dx to obtain d y = f ( x) d x dy=f (x)~dx dy = f (x) dx Step 2 Then we take the integral of both sides to obtain ∫ d y = ∫ f ( x) d x y C ′ = ∫ f ( x) d x ⇒ y = ∫ f ( x) d x, \begin {aligned} \int dy&=\int f (x)~dx\\ yC'&=\int f (x)~dx\\ \Rightarrow y&=\int f (x)~dx, \end {aligned} ∫ dy y C ′Calculus 1 Answer Sonnhard #y'=x^(x^2)(2xln(x)x)# Explanation Taking the logarithm on both sides we get #ln(y)=x^2ln(x)# differentiating with respect to #x# #1/y*y'=2xln(x)x# so we get #y'=x^(x^2)(2xln(x)x)# Answer link Related questions
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Find dy/dx if y= xe^x / x e^x Get the answers you need, now! Y= x^x^2 , then dy/dx is ? We can now readily differentiate wrt x by applying the chain rule (or implicit differentiation the LHS and the chain rule and the product rule on the RHS 1 y dy dx = (sinx)( 1 sinx cosx) (cosx)lnsinx Which we can simplify 1 y dy dx = cosx cosx lnsinx ∴ dy dx = y{cosx cosx lnsinx} = ycosx{1 lnsinx}
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If y = f((2x 1)/(x^2 1)) and f'(x) = sinx^2, then dy/dx is (A) cosx^2f'(x) asked in Limit, continuity and differentiability by Vikky01 ( 418k points) differentiation1) у %3 3t5 – 2t x = 4t³ 2) y = t3 – 7 , x= t² – 2t 3) у %3D 2u* 1 x = 5u?– 5u 4) y = v2t – 5 , x = t² – 3 5) у %3D 2t3 – 3t x = 4t2 4t 1
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If `x^(2)y^(2)=a^(2)`, then the value of `(dy)/(dx)` is A `(x)/(y)` B `(x)/(y)` C `(y)/(x)` D `(y)/(x)` Welcome to Sarthaks eConnect A unique platform whereLet y = y(x) be the solution of the differential equation `x dy/dxy=xlog_ex,(xgt1)" If " 2y(2)=log_e41," then "y(e)` is equal to asked 4 days ago in Mathematics by Sowaiba ( x^y y^x = (x y)^ (xy) Take logs y ln (x) x ln (y) = (xy) ln (xy) Differentiate wrt x (dy/dx) ln (x) y (1/x) ln (y) x (1/y dy/dx) = (1dy/dx) ln (xy) (xy) 1/ (xy) dy/dx (dy/dx) ln (x) y/x ln (y) x/y dy/dx = (1dy/dx) ln (xy) dy/dx
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Click here👆to get an answer to your question ️ If cos (x y) = y sin x , then find dydx Solve Study Textbooks Guides Join / Login >> Class 12 >> Maths >> Continuity and Differentiability >> Derivatives of Implicit Functions >> If cos (x y) = y sin x , then find dy Question If cos (x y)Implicit differentiation can help us solve inverse functions The general pattern is Start with the inverse equation in explicit form Example y = sin −1 (x) Rewrite it in noninverse mode Example x = sin (y) Differentiate this function with respect to x on both sides Solve for dy/dxThe partial derivative of u(x,y) with respect to x is \frac{\partial u}{\partial x}=yx^{y1}\ln{y}\;
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If x > 0 and xy = 1, the minimum value of (x y) is A 2 B 1 C 2 D none of these asked in Derivatives by Gargi01 ( 507k points) applications of derivativesWe have y = xe2y Taking log on both sides, we get logy = log(xe2y)⇒ logy = logx2yloge⇒ logy = logx2yOn differentiating w r t x, we get y1 dxdy = x1 2dxdy ⇒ dxdy (y1 −2) = x1 ⇒ dxdy = x1 × (1−2y)y ⇒ dxdy = x(1−2y)ySolution for dy dx?
Solved Ticremuation B Solve The Equation Explicitly For And Differen In Terms Of X C Check That Your Solutions To Parts A And B By Substituting The Expression For Y Into Your Part
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1/2 ln((y/x)^21) arctan (y/x) = ln x C dy/dx=(xy)/(xy) this is first order linear and homogeneous in the sense that when written in the form dy/dx = f(x,y) then f(kx, ky) = f(x,y) so we rewrite it as dy/dx=(1y/x)/(1y/x) in order to make the standard sub v(x) = (y(x))/x because y = v x, then y' = v' x v so we have v'x v = (1v)/(1v) and we may as well now x y y x = a b, here ab is const let x y = u ;To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `(dy)/(dx)` = 1 x y xy and y (1) = 0, then function y is
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If x y y x = a b, find dy/dx cbse;Solution Given y = x x Take log on both sides log y = x log x Differentiate wrtx (1/y)dy/dx = x (1/x) log x = 1 log x dy/dx = y (1 log x) = x x (1 log x)Q Find and d²y then simplify whenever possible dx dx² 1) у %3D 3t5 — 2t x = 4t3 2) y = t3 – 7 x = t² A As per the request of student 4th and 5th answer has
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The` (dy)/(dx)=6x` then y = A `cot theta theta` B ` cot theta theta c ` C ` cot theta theta c ` D ` cot theta theta c `Y^x It is calculated like the derivative, but assuming that y is a constant, ie not a function oTake log on both sides == x log y = logv == x*1/ydy/dx logy*1 (by products rule) = 1/v dv/dx == dv/dx = y x (x/y dy/dx logy) == u v = a b differentiating wrt x we get , du/dx dv/dx = 0 ==
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